Henry launched a model rocket with an initial speed of 88 feet per second. The equation h(t) =− 16t^2+vt models the trajectory of the rocket. After how many seconds will the rocket be 40 feet high?

step-by-step explanation:

there's the chart

answer: 180 degrees clockwise

step-by-step explanation:

46

step-by-step explanation:

given

height = 168 cm

formula

height =2.47*f+54.13

solution

168 = 2.47f + 54.13             subtract 54.13 from both sides

168 - 54.13   = 2.47f             combine

113.87 = 2.47f                     divide by 2.47

113.87 / 2.47 = f                   combine

46.1 = f  

answer: 46 cm

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3