Sunnyville's population is 14,000, and it is increasing by 160 people every year. Beachville's population is 24,000 and it is decreasing by 90 people every year. In how many years, y, will the population of Sunnyville exceed the population of Beachville? 14,000+160y≥24,000−90y
14,000 + 160 y is greater than equal to 24,000 - 90 y

14,000+160y<24,000−90y
14,000+160y<24,000−90y

14,000+160y>24,000−90y
14,000 + 160 y < 24,000 - 90 y

14,000+160y=24,000−90y

number of years, y, at which the population of Sunnyville will exceed the population of Beachville is when y is more than 40 years.

Step-by-step explanation:

From the question the inequality that depicts when the population of Sunnyville exceed the population of Beachville is given as;

14,000 + 160y ≥ 24,000 − 90y

Adding 90y to both sides gives;

14,000 + 160y + 90y ≥ 24,000 − 90y + 90y

14,000 + 250y ≥ 24,000

Subtracting 14000 from both sides;

14,000 - 14000 + 250y ≥ 24,000 - 14000

250y ≥ 10000

y ≥ 10000/250

y ≥ 40

Thus, number of years, y, at which the population of Sunnyville will exceed the population of Beachville is when y is greater than 40 years.

step-by-step explanation:

i think you should think about the question and not look online.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!