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Mathematics, 09.10.2020 14:01 harri26348

Evaluate 6t -20-32u6tโˆ’20โˆ’32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u= 4
1

u, equals, start fraction, 1, divided by, 4, end fraction.

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Evaluate 6t -20-32u6tโˆ’20โˆ’32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=...
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