Twice the sum of a number and 3 is equal to three times the difference of the number and 7. Find the number

The number is 27

Step-by-step explanation:

Let us change the word statement to an algebraic equation

→ Assume that the number is x

→ Twice the sum of a number and 3, means add x by 3, then multiply the sum by 2

→ The algebraic expression is 2(x + 3)

→ Three times the difference of the number and 7, means subtract x and 7, then multiply the difference by 3

→ The algebraic expression is 3(x - 7)

→ Equate the two expressions

∴ 2(x + 3) = 3(x - 7)

→ Simplify each side

∵ 2(x + 3) = 2(x) + 2(3) = 2x + 6

∵ 3(x - 7) = 3(x) - 3(7) = 3x - 21

∴ 2x + 6 = 3x - 21

Let us solve the equation to find x

→ Subtract 6 from both sides

∴ 2x + 6 - 6 = 3x -21 - 6

∴ 2x = 3x - 21

→ Subtract 3x from both sides

∴ 2x - 3x = 3x - 3x - 27

∴ -x = -27

→ Divide both sides by -1

∴ x = 27

The number is 27

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}