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Mathematics, 08.10.2020 02:01 howell62
Identify the correct steps used to prove the formula βnj= 1(ajβ ajβ1)= anβ a0 , where a0, a1, . . . , an is a sequence of real numbers. (Check all that apply.) Check All That Apply The explicit form of the summation is: βnj= 1(ajβ ajβ 1) = a1β a0+ a2β a1+ a3β a2+ ...+ anβ anβ 1 The explicit form of the summation is: βj = 1 n ( aj β aj β 1 ) = a1 β a0 + a2 β a1 + a3 β a2 + ... + an β an β 1 The explicit form of the summation is: βnj= 1(ajβ ajβ 1) = a1β a0+ a2β a1+ a3β a2+ ... + anβ anβ 2 The explicit form of the summation is: βj = 1 n ( aj β aj β 1 ) = a1 β a0 + a2 β a1 + a3 β a2 + ... + an β an β 2 The reduced Explicit form = -a0 + (a1 - a1) + (a2 - a2) + + (an - 1 - an - 1) + an = an - a0 The reduced Explicit form = -a0 + (a1 - a1) + (a2 - a2) + + (an - 1 - an - 1) + an = an - a0 The reduced Explicit form = -a0 + (a1 - a2) + (a2 - a1) + + (an - 1 - an - 2) + an = an - a0
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Identify the correct steps used to prove the formula βnj= 1(ajβ ajβ1)= anβ a0 , where a0, a1, . . ....
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