Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 5 of the respondents did not provide a response, said that their experience fell short of expectations, and of the respondents said that their experience met expectations. Round your answers to two decimal places. a. If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations

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Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 5% of the respondents did not provide a response, 26% said that their experience fell short of expectations, and 65% of the respondents said that their experience met expectations. Round your answers to two decimal places.

a. If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations

b. If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?

a) 0.04

b) 0.69

Step-by-step explanation:    

Given that

P ( No response ) = 5% = 0.05

P ( Short of expectation ) = 26 = 0.26

P ( Met expectation ) = 65% = 0.65

a)  the probability that the alumnus would say their experience surpassed expectations

P ( surpassed expectations) = 1 -  (P(No resp )+P( Short of exp)+ P( Met exp))

= 1 - (0.05 + 0.26 + 0.65 )

= 1 - 0.96

= 0.04

b) the probability that the alumnus would say their experience met or surpassed expectations.

the probability that  experience met or surpassed expectations is;

= P (met exp) + P ( surpassed exp)

= 0.65 + 0.04

= 0.69

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w