WidgCo is a company that produces and sells widgets. Let p denote the price per widget (measured in dollars), and let x be the monthly demand for widgets. WidgCo's marketing department determines that p and x are related by the following demand equation: p(x) = 211 − 5x. The cost of producing x widgets is given by C(x) = 1,401 + 16x. Construct the revenue function, R(x). Find the production level that will result in the maximum revenue. Find the maximum monthly revenue. Enter your answer to part c in the box below. Round your answer to the nearest cent.

The maximum monthly revenue of WidgCo is; $489

price function; p(x) = 211 - 5x

Cost function; C(x) = 1401 + 16x

Revenue = number of units sold × price per unit

Thus;

R(x) = x(211 - 5x)

Expanding this gives;

R(x) = 211x - 5x²

R'(x) = 211 - 10x

At R'(x) = 0, we have;

211 - 10x = 0

x = 211/10

x = 21.1

x ≈ 21 widgets

Maximum Revenue is;

R(20) = 195(21) - 1401 - 5(21)²

R(20) = $489

Read more about revenue function at; link

The answer to this question can be defined as follows:

i)

ii) x=22 units

iii) Maximum profit: 953.45

Step-by-step explanation:

Given value:

p(x) = 211 − 5x \\

C(x) = 1,401 + 16x

The formula for calculating the profit function value:

The formula for calculating the value for maximum profit:

So, the production level is 22 units

Maximum profit:

6hryt%4578855

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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