Mathematics, 07.10.2020 07:01 gwendallinesikes

In 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to complete the 42.2 km (26.2 mile) race. If 100 runners are chosen at random, find the probability that exactly 97 of them finished the marathon

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Answer from: oryunnis

Using the binomial distribution, it is found that there is a 0.2207 = 22.07% probability that exactly 97 of them finished the marathon.

For each runner, there are only two possible outcomes, either they finished the marathon, or they did not. The probability of a runner finishing the marathon is independent of any other runner, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.

In this problem:

97.4% of all runners finished the marathon, hence p = 0.974

.100 runners are chosen at random, hence n = 100

The probability that exactly 97 of them finished the marathon is P(X = 97), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 97) = C_{100,97}.(0.974)^{97}.(0.026)^{3} = 0.2207$

There is a 0.2207 = 22.07% probability that exactly 97 of them finished the marathon.

A similar problem is given at link

Answer from: lillianneal

The probability that exactly 97 of them finished the marathon is 0.221.

Step-by-step explanation:

We are given that in 2019, approximately 97.4% of all the runners who started the Boston Marathon were able to complete the 42.2 km race.

100 runners are chosen at random.

The above situation can be represented through the binomial distribution;

$P(X = x) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x = 0,1,2,3,......$

where, n = number of trials(or samples) taken = 100 runners

r = number of success = exactly 97

p = probability of success which in our question is the probability

that runners finished the marathon, i.e; p = 0.974

So, X ~ Binom(n = 100, p = 0.974)

Now, the probability that exactly 97 of them finished the marathon is given by = P(X = 97)

P(X = 97) = $\binom{100}{97} \times 0.974^{97} \times (1-0.974)^{100-97}$

= $161700 \times 0.974^{97} \times 0.026^{3}$

= 0.221

Hence, the required probability is 0.221.

Answer from: Quest

The answer to your question is b’(16,14)

Answer from: Quest

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

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