the length of a rectangle is 24 feet more than the width. The perimeter of the rectangle is 88 feet. What is the length and width of this rectangle?

The length of the rectangle is 34 feet.

The given parameters;

The length of the rectangle is calculated as follows;

P = 2(L+ w)

P = 2(24 + w + w)

P = 2(24 + 2w)

88 = 48 + 4w

subtract 48 from both sides of the equation;

88 - 48 = 4w

40 = 4w

w = 10

Now, solve for the length;

L = 24 + w

L = 24 + 10

L = 34 feet

Thus, the length of the rectangle is 34 feet.

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W = 10 ft

Step-by-step explanation:

Represent the length by L and the width by W.  Then L = W + 24.

The perimeter is P = 2W + 2L, or 88 ft.  Thus, after substituting L = W + 24,

88 ft = 2W + 2(W + 24), or

88 = 2W + 2W + 48, or, after reduction,

44 = 2W + 24, or

2W = 20, and so W = 10 ft

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