Solve 3^x−5 = 9. please

Assuming the -5 is with the x

You have 3^(x-5) =9

Convert the 9 to base 3: 3^2 = 9

Now you have:

3 ^(x-5) = 3^2

Now solve for exponents:

X-5= 2

Add 5 to both sides:

X = 7

add 5 subtract 1

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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