The weights of Sarus crane chicks and hooded crane chicks H (both in grams) during the 10 days following hatching can be modeled by the functions S = –0.122t3 + 3.49t2 – 14.6t + 136 H = –0.115t3 + 3.71t2 – 20.6t + 124 where t is the number of days after hatching. According to the models, what is the difference in weight between 5-day-old Sarus crane chicks and hooded crane chicks? Round your answer to the nearest thousandth, if necessary.

Step-by-step explanation:

Given

Functions:

Finding the difference between S(5) and H(5)

Answer is 35.875 grams

594 square inches

step-by-step explanation:

vote !

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet