Select all the conditions for which it is possible to construct a triangle. Group of answer choices

A triangle with angle measures LaTeX: 60^\circ 60 ∘ , LaTeX: 80^\circ 80 ∘ , and LaTeX: 80^\circ 80 ∘

A triangle with side lengths 4 cm, 5 cm, and 6 cm

A triangle with side lengths 4 cm, 5 cm, and 15 cm

A triangle with side lengths 4 cm and 5 cm and a LaTeX: 50^\circ 50 ∘ angle

A triangle with angle measures LaTeX: 30^\circ 30 ∘ and LaTeX: 60^\circ 60 ∘ , and a 3 cm side length

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.