Compare an angle having a measure of 120° With that of an angle whose measure is five pi over 6 rad explain your reasoning

Step-by-step explanation:

et A=120°

and B=5Pi /6

Pi radians > 180°

  x< 120°

so x =120 x Pi / 180 = 12 xPi / 18 = 2 Pi/3

so A = 2Pi / 3 radian  

let 's compare A and B

we know that 5Pi /6 = 0.8 Pi and  2P/3= 0.6 Pi, 0.8>0.6,  

finally 5Pi /6 > 2P/3

so B>A

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form