What values of c and d would make the following expression represent a real number?
i(2 +31)(c + di)
O c= 2, d = 3
O C= -2, d = 3
Oc=3, d = -2
Oc=-3, d=-2

answer: i don't understand it

step-by-step explanation: sorry

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function

-3 degrees

step-by-step explanation: