ruger has a dartboard with an area of 1600 cm^2. The dartborad has a circular bullseye centered at (0 cm, 0 cm). The point ( square root 3cm, square root 7cm) is on the circumference of the bullseye.

A percentage is given by dividing a given value by a total and multiplying the result by 100

The percentage of the dartboard occupied by the bullseye is approximately 1.963 %

Reason:

The given parameters are;

The area of the dartboard, A = 1,600 cm²

The location of the center of the bullseye = (0 cm, 0 cm)

The coordinates of a point on the circumference = (√3 cm, √7 cm)

Question: Possible question with regards to the given parameter; The percentage of the dartboard covered by the bullseye

Solution;

The radius of the bullseye, r =

The area of the bullseye, = π· r² = π × = 10·π

∴ The area of the bullseye, = 10·π cm²

The percentage area is given as follows;

Therefore;

The percentage of the dartboard occupied by the bullseye ≈ 1.963 %

Learn more about percentage area here:

link

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk