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Mathematics, 05.10.2020 16:01 Jake10383

The work of a student to solve the equation 4(2x βˆ’ 4) = 8 + 2x + 8 is shown below: Step 1: 4(2x βˆ’ 4) = 8 + 2x + 8 Step 2: 6x βˆ’ 8 = 16 + 2x
Step 3: 6x βˆ’ 2x = 16 + 8
Step 4: 4x = 24
Step 5: x = 6
In which step did the student first make an error and what is the correct step? Group of answer choices
Step 2; 8x βˆ’ 4 = 2(6 + x + 6)
Step 2; 8x βˆ’ 16 = 16 + 2x Step 3; 6x βˆ’ 2x = 16 βˆ’ 8
Step 3; 6x + 2x = 16 + 8

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The work of a student to solve the equation 4(2x βˆ’ 4) = 8 + 2x + 8 is shown below: Step 1: 4(2x βˆ’ 4)...
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