F(x) = x2 + 3; g(x) = sqrt of (x-2)
Find f(g(x)).

f(g(x)) = x + 1

Explanation:

g(x) = sqrt of (x-2)
f(x) = x^2 + 3

So f(g(x)) = f(sqrt(x-2))

Replace the value of the x with sqrt(x-2)
=> f(sqrt(x-2)) = sqrt(x-2)^2 + 3

Sqrt and the square cancel each other

= x -2 + 3
= x + 1

Thus, f(g(x)) = x+1