A helicopter flying 1,600 feet above the ground spots an airplaneflying above. If the horizontal distance between the helicopter andairplane is 3,055 feet and the angle of elevation is 71°, find theairplane’saltitude

10472. 4 ft

Step-by-step explanation:

Let the height of the plane above the helicopter be "h"  

We have a right triangle  where  the side opposite the 71 degree angle  =  h   and the side adjacent to this angle =  3055

So   we can use the tangent here

tan (71)  =  h / 3055       multiply both sides by 3055

3055 * tan (71)  =  h ≈   8872.4  ft

Sothe total altitude of the plane is

1600 + 8872.4  =

10472. 4 ft

sorry i got nothing

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.