Find the equation of the line that passes through the point (2, 1) and is perpendicular to y=(−2/5)x+3.

Step-by-step explanation:

perp. 5/2

y - 1 = 5/2(x - 2)

y - 1 = 5/2x - 5

y = 5/2x - 4

The answer is

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the perpendicular line we must first find the slope of the original line

The original line is y = - 2/5x + 3

Comparing with the general equation above

Slope/m = - 2/5

Since the lines are perpendicular to each other the slope of the perpendicular line is the negative inverse of the original line

So we have

So the slope of the perpendicular line is

5/2

So the equation of the line using point

(2, 1) and slope 5/2 is

We have the final answer as

Hope this helps you

b is the final answer! : )

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐