Let v(t)=t2−2tv(t)=t2−2t be the velocity, in feet per second, of an object at time tt, in seconds.
(a) what is the initial velocity?
(b) when does the object have a velocity of zero? if there is more than time, list all answers in a comma separated list.

v(0) =0

t=0,2

Step-by-step explanation:

Given that velocity in feet per second of an object  at time t in seconds is given by the quadratic equation

Initial velocity is the velocity at time 0.

Substitute t=0 in v(t)

a) Initial velocity =

b) Equate velocity function to 0 and solve for t.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )