The ages (in years) and heights (in Inches) of all pitchers for a baseball team are listed. Find the coefficient of variation for each of the two data sets. Then compare the results.
***data set in picture attached***

CV heights= __% (Round to one decimal place as needed.)

a) Coefficient of Variation for Height = 4.46%

b) Coefficient of Variation for Ages

= 12.26%

c)Comparing both Variations, the coefficient of variation for ages is larger than that of the mean and this is due to the fact that the

Step-by-step explanation:

Coefficient of Variation formula = Standard deviation / Mean × 100%

From the attached diagram, we are given sample data

1) For the Height

a) Mean of the Heights

= Sum of term/ Number of terms

= 74 + 70 + 70 + 76 + 77 + 72 + 75+ 70 + 70 + 80 + 75 + 75/12

= 884/12

= 73.66666667

b) Standard Deviation of Heights

For Sample data, the formula

=√ (X - Mean)²/n - 1

= 3.284490644

c) Coefficient of variation for Heights

Coefficient of Variation formula = Standard deviation / Mean × 100%

=( 3.284490644/73.66666667) × 100

= 0.04458584584 × 100

= 4.45858458441%

≈ 4.46%

2) Mean of ages

= Sum of terms/ Number of terms

= 21 + 26 + 22 + 27 + 29 + 26 + 27 + 29 + 30 + 31 + 31 + 31/12

= 330/12

= 27.5

b)Standard Deviation of Ages

For Sample data, the formula

=√ (X - Mean)²/n - 1

= √ (21 - 27.5)² + (26- 27.5)² +( 22- 27.5)² + (27- 27.5)² + (29- 27.5)² +( 26- 27.5)² +( 27- 27.5)² + (29- 27.5)² + (30 - 27.5)² + (31- 27.5)² + (31- 27.5)²+ (31- 27.5)²/12

=√ -6.5² + -1.5² + -5.5²+ -0.5² + 1.5² + -1.5² + -0.5² + 1.5² + 2.5² +3.5² + 3.5² + 3.5²/ 11

= √125/11

= √11.36363636

= 3.370999312

c) Coefficient of Variation

= Coefficient of Variation formula = Standard deviation / Mean × 100%

= (3.370999312/27.5) × 100

= 0.12258179316 × 100

= 12.258179316%

step-by-step explanation:

is this part of a question or something