Suppose that scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 18. Using the empirical rule, what percentage of IQ scores are greater tha 79? Please do not round your answer .

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

answer: do we write it

step-by-step explanation:

answer: i think one of the answer is $150 and $300?

step-by-step explanation: