What are the first five sequences to the equation f(1)=2/3,f(n)=f(n-1)x3/2

2/3,1,3/2,9/4,27/8

Step-by-step explanation:

f(1)=2/3

f(n)=f(n-1)×3/2

f(2)=f(2-1)×3/2=f(1)×3/2=2/3×3/2=1

f(3)=f(3-1)×3/2=f(2)×3/2=1×3/2=3/2

f(4)=f(4-1)×3/2=f(3)×3/2=3/2×3/2=9/4

f(5)=f(5-1)×3/2=f(4)×3/2=9/4×3/2=27/8

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step-by-step explanation: