Drag each expression or value to the correct box. Not all tiles will be used. Luke started a weight-loss program. The first week, he lost x pounds. The second week, he lost pounds 3/2 less than 3/2 times the pounds he lost
the first week. The third week, he lost 1 pound more than 3/4 of the pounds he lost the first week.
Liam started a weight-loss program when Luke did. The first week, he lost 1 pound less than 3/2 times the pounds Luke lost the first week. The second week, he lost 4 pounds less than 5/2 times the pounds Luke lost the first week. The third week, he lost 1/2 pound more than 5/4 times the
pounds Luke lost the first week.
Assuming they both lost the same number of pounds over the three weeks, complete the following sentences.

13/4x - 1/2
9/4x - 9/2
2 pounds
4 pounds
6 pounds
21/4x - 9/2

The expression for Luke's weight loss over the three weeks is

The expression for Liam's weight loss over the three weeks is

The number of pounds Luke lost in the first week is

The number of pounds Luke and Liam each lost over the three weeks is

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.