Dont solve just find the system of equations A food store makes a 6-lb mixture of walnuts, cashews, and dates. The cost of walnuts is $1.50 per pound, cashews cost $1.00 per pound, and dates cost $1.50 per pound. The mixture calls for twice as many walnuts as cashews. The total cost of the mixture is $8.50. Which system of equations could be used to find the amount of each ingredient the store used?

3y + x = 6

4y + 1.50x = 8.50

Step-by-step explanation:

Cost of walnut = $1.50

Cost of cashew = $1.00

Cost of dates = $1.50

Let

Dates = x

Cashew = y

Walnuts = 2y

Pounds of total mixture = 6 lb

Total cost of the mixture = $8.50

First equation (from Quantity)

Walnuts + cashew + dates = Total mixture

2y + y + x = 6

3y + x = 6

Second equation (from price× Quantity)

2y(1.50) + y(1.00) + x(1.50) = 8.50

3y + y + 1.50x = 8.50

4y + 1.50x = 8.50

Therefore, the system of equation to solve the question is

3y + x = 6

4y + 1.50x = 8.50

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!