Which graph represents the same relation as the set StartSet (negative 3, 2), (5, 5), (3, 3), (3, negative 2) EndSet? A coordinate plane has 3 points. The points are (negative 3, 2), (3, negative 2), (5, 5). A coordinate plane has 4 points. The points are (negative 3, 2), (3, negative 2), (3, 3), (5, 5). A coordinate plane has 7 points. The points are (negative 3, 0), (0, 5), (0, 3), (0, 2), (0, negative 2), (3, 0), (5, 0). A coordinate plane has 4 points. The points are (negative 2, 3), (2, negative 3), (3, 3), (5, 5).

answer is 12345678900987654321234567890987654321

step-by-step explanation:

part d

step-by-step explanation:

theresa talked her parents into getting sd cards for her phone and her brother’s phone. inserting an sd card into a phone gives it more storage. they both get 8-gigabyte sd cards. how many bits of storage come with each sd card? type your answer in both scientific and standard notation.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)