Marcus is buying 10 gift bags for his birthday party. he will choose items to put in the bags and then pay an additional charge of $0.75 for the actual bag. marcus cannot spend more than $50. write and solve an inequality to find the most marcus can spend on the items for each bag.

Answer with Step-by-step explanation:

Let cost of items for 10 bags be represented by x

Cost of 1 bag=$ 0.75

Cost of 10 bags=$ (0.75×10)

                         = $ 7.5

Total cost of 10 bags with items in them=$(7.5+x)

Marcus cannot spend more than $50.

i.e. 7.5+x≤50

Subtracting both sides by 7.5

x≤42.5

Most Marcus can spend for items in 10 bags=$42.5

Most Marcus can spend for items in 1 bag=$(42.5/10)=$4.25

Hence, most Marcus can spend on the items for each bag is:

$4.25

step-by-step explanation:

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.