The sum of the ages of three brothers Tema, Juma and Abdul is 65 years. Juma is twice as old as Abdul and a half times as old as Tema. Determine their present age

Tema = 26 years

Juma = 13 years

Abdul = 26 years

Step-by-step explanation:

Let their ages be represented as:

Tema = x

Juma = y

Abdul = z

From the question, we are told that:

Juma is twice as old as Abdul

y = 2z

z = y/2

= 0.5y

And Juma is a half times as old as Tema.

y = 1/2x

y = 0.5x

x = y/0.5

x = 2y

Hence,

x + y + z = 65

2y + y + 2y = 65

= 5y = 65

y = 65/5

y = 13 years

Since y = Zuma's age, Zuma is 13 years old

From the above question

Since 2y = z

y = 13

2 × 13 = z

z = 26

Since z = Abdul's age, Abdul is 26 years old

From the above question

x = 2y

y = 13 years

x = 2 × 13 years

x = 26 years.

Since x = Tema's age

Tema is 26 years.

Therefore, their present ages are:

Tema = 26 years

Juma = 13 years

Abdul = 26 years

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!