A new outdoor recreation center is being built in Hadleyville. The perimeter of the rectangular playing field is 316 yards. The length of the field is 4 yards less than twice its width. What are the dimensions of the playing field?

Given :

Perimeter of rectangular filed , P = 316 yards.

The length of the field is 4 yards less than twice its width.

To Find :

The dimensions of the playing field.

Solution :

Let, width be x.

So, by given condition length will be 2x - 4.

Perimeter is given by :

P = 2( l + b )

316 = 2( 2x - 4 + x )

3x - 4 = 158

x = 54 yards.

So, the dimensions are 54 yards and 104.

Hence, this is the required solution.

sine

step-by-step explanation: