A square image of an object on a video game has an initial side length of 25 pixels. To make the object appear closer, the side length of the square is increased by 10 pixels per second. This length change is represented by the function s(t) = 25 + 10t, where t is time in seconds. If the area of the square is A(s) = s², find the formula for the area as a function of time, and then determine A(s(3)).

A(t) equals
t²+
t + 625.

The area of the square image after 3 seconds is
3,025
square pixels.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.

the answer is b 4pi/3

got it down chief.