Let ∑k=1[infinity](−1)k+1ak be a convergent alternating series with terms that are nonincreasing in magnitude. Let Rn=S−Sn be the remainder in approximating the value of that series by the sum of its first n terms. Then Rn≤an+1. In other words, the magnitude of the remainder is less than or equal to the magnitude of the first neglected term. For the convergent alternating series ∑k=0[infinity] (−1)k (2k+1)4, evaluate the nth partial sum for n=2. Then find an upper bound for the error S−Sn in using the nth partial sum Sn to estimate the value of the series S.

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.

answer: 7 x 2/5 = 2.8 hours, is your answer. your welcome! : 3

step-by-step explanation: first work out how long it took to hose 1/7 of the lawn which is 2/5 hours. times that by 7 to get the whole lawn.

sorry i don't know the other answer. i didn't learn what a proportional relationship is.