Consider a parallelogram with vertices a-(0,0), b = (9,3) , c = (1,8) , and d depicted below. (10,11) , as (a) Let u b-a and v-c-a. Compute two vectors u and v. (b) Compute the base length w of the parallelogram, which is the length of vector u.
(c) Compute the height h of the parallelogram using vector projection.
(d) Compute the area of the parallelogram A wh.

answer: haha (: i’ll go see what it is

step-by-step explanation:

kjgfcvbjkl

step-by-step explanation:

sdfghjkl; vbnm,

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81