Write the equation of each pair of parabola in vertex form. a. Vertex:(1,2); Point:(2,-5)
b. Vertex: (3,6); y-intercept: 2
c. Vertex: (0,5); Point:(1, -2)

 (a) y = -7(x - 1)² + 2

               (b) y = 4/9(x - 3)² + 6

               (c) y = -7x² + 5

Step-by-step explanation:

The vertex form of a quadratic equation is: y = a(x - h)² + k    where

Input the vertex (h, k) and the point (x, y) into the equation to solve for "a"

(a)   Vertex (h, k) = (1, 2)  Point (x, y) = (2, -5)

       y = a(x - h)² + k

       ↓      ↓    ↓     ↓

     -5 = a(2 - 1)² + 2

     -7 = a(1)²

     -7 = a

(b)   Vertex (h, k) = (3, 6)  Point (x, y) = (0, 2)

       y = a(x - h)² + k

       ↓      ↓    ↓     ↓

      2 = a(0 - 3)² + 6

     -4 = a(-3)²

     -4 = -9a

   4/9 = a

(c)   Vertex (h, k) = (0, 5)  Point (x, y) = (1, -2)

       y = a(x - h)² + k

       ↓      ↓    ↓     ↓

     -2 = a(1 - 0)² + 5

     -7 = a(1)²

     -7 = a

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves