The freezing temperature of water is 32 degrees Fahrenheit and the boiling temperature of water is 212 degrees Fahrenheit. Write an absolute value equation that represents the minimum and maximum temperature of liquid water. Use x to represent the temperature.

32°F ≤ x ≤ 212°F

Step-by-step explanation:

Let's use the letter x to denote our variable, the temperature.

We know that water starts freezing at 32°F (this is the transition point, so when liquid water reaches this point it will remain at that temperature until all the water changes tho the solid phase, ice).

Then the minimum temperature of the liquid water is 32°F, we can write this as:

32°F ≤ x

We also know that at 212°F the water starts boiling, this means that when liquid water reaches the temperature of 212°F, any increase in energy (or any quantity of heat that you give to the water) will only change the phase of the water, so we can have liquid water at the temperature of 212°F, and the temperature will only increase when all the water is transformed into vapor.

We write this as:

x ≤ 212°F

Now, writing both inequalities we have:

32°F ≤ x ≤ 212°F

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.