A normal population has the mean of 10 and the variance of 25 . A random sample of size n-28 is selected. (a) Find the standard deviation of the sample mean. Round your answer to two decimal places (e. g. 98.76)
(b) How large must the sample be if you want to halve the standard deviation of the sample mean?

Step-by-step explanation:

Given that:

population mean = 10

variance = 25  ; = = 5

sample size n = 28

The standard deviation of the sample mean:

=

= 0.95

To halve the standard deviation of the sample mean, the size of how large the sample will be can be computed as follows:

= 2

n = 4 × 28

n = 112

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

i dont know men

step-by-step explanation: