PLEASE HURRY I NEED HELP I TRIED FOUR DIFFERENT TIMES ON THIS EQUATION AND I DON'T UNDERSTAND WHAT TO DO (will give brainliest for best answer) image below

The answer is 48a-6b-14

Step-by-step explantion:

simplify by combining liketerms:

-6- 2b•3 -6a+ 10a• 3-16÷ 2- 4 • -6a

-6-6b-6a+30a -8+24a

48a-6b-14

Good luck!

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: y=0 if that is what u r looking for