Consider the composite function (g (x) ) = StartRoot StartFraction 1 Over x squared minus 3 EndFraction EndRoot. If g(x) = x2 – 3, what is f(x)? f (x) = StartRoot StartFraction negative 1 Over x EndFraction EndRoot
f (x) = StartRoot StartFraction negative 1 Over x + 6 EndRoot EndFraction
f (x) = StartRoot StartFraction 1 Over x EndFraction EndRoot
f (x) = StartRoot StartFraction 1 Over x + 6 EndFraction EndRoot

the answer would be StartRoot 2 EndRoot

Step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b