Please help How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 55% antifreeze?

Assume that x gallon water is added: 35% antifreeze

= 1 / (x + 1) = 0.35

1 = 0.35 x + 0.35

0.65 = 0.35(x)

x = 1.857 gallons

The answer is 1.89 gallons of waters should be added to 1 pure antifreeze to obtain a solution that is 35% antifreeze.

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

i belive those are the ones that are under 90 degreese.