Two bags each contain tickets numbered 1 to 10. John draws a ticket from each bag five times, replacing the tickets after each draw. He records the number on the ticket for each draw from both the bags: Bag 1Bag 2 Draw 124 Draw 245 Draw 313 Draw 464 Draw 579 For the the first bag, the mean is 4 and the standard deviation is 2.5. For the second bag, the mean is 5 and the standard deviation is 2.3. Using the formula below or Excel, find the correlation coefficient, r, for this set of tickets John drew. Answer choices are rounded to the nearest hundredth. r equals fraction numerator 1 over denominator n minus 1 end fraction sum from blank to blank of open parentheses fraction numerator x minus x with bar on top over denominator s subscript x end fraction close parentheses open parentheses fraction numerator y minus y with bar on top over denominator s subscript y end fraction close parentheses 0.50 0.56 0.70 0.75

0.75

Step-by-step explanation:

Given the following :

Using the formula above :

___bag 1__bag 2__(bag1-m)/sd__(bag2-m)/sd2

D 1___24-0.8-0.4

D 2___4500

D 3___13-1.2-0.9

D 4___6___ 40.8-0.4

D 5___7___9 1.2 1.7

Bag1:

Mean = 4

Standard deviation = 2.5

Bag2:

Mean = 5

Standard deviation = 2.3

Σ-0.8*-0.4 + 0 + - 1.2*-0.8 + 0.8*-0.4 + 1.2*1.7) = 3

1/ (n-1) × 3

1/(5 - 1) × 3

(1/4) × 3

0.25 * 3 = 0.75

14

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.