H(x) = 3x + 3
g(x)=-4x + 1
Find (h+ g)(10)
How to solve this ?

h(x ) = 3 x+ 3

 g ( x ) = − 4 x + 1

( h +g ) ( x ) = 3 x + 3 − 4 x + 1 = − x + 4

( h + g ) ( 10 )

= − 10 + 4  

= − 6

Step-by-step explanation:

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when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.