Line segment JK in the coordinate plane has endpoints with coordinates \left(-4,11\right)(−4,11) and \left(8,-1\right)(8,−1).Supposed J, P, and K are collinear on segment JK, and JP:JK=\frac{1}{3}JP:JK=1/3 . What are the coordinates of P?

Step-by-step explanation:

Given P to be the point that divides the coordinates J and K in the ratio 1:3

then the coordinate of point P will be xpressed as;

P(X, Y) =

Given J = (-4, 11) and K = (8, -1)

substituting the given parameters into the line division formula

Hence the coordinates of P is (-1, 8)

n

step-by-step explanation: