You intend to estimate a population mean μ with the following sample. 78.4, 85.3, 50, 68.4, 59.4, 73.7, 73.2, 47.4, 40.5 You believe the population is normally distributed.
Find the 99.5% confidence interval.
The answer must be done as an open-interval accurate to 2 decimal places.

(17.75, 110.32)

Step-by-step explanation:

The sample mean is 64.03, and the standard deviation is 15.43.

The population is normally distributed, so 99.5% confidence is ±3 standard deviations.

The confidence interval is therefore:

(64.03 − 3 × 15.43, 64.03 + 3 × 15.43)

(17.75, 110.32)

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation:

did u ever get the answers? i need