Mathematics, 20.09.2020 09:01 MJyoungboy

An airplane flies at an altitude of 14,690 ft while a submarine is submerged at a depth of 521 feet below the surface of the ocean.. What is the difference between these two elevations? Write an algebraic expression for the given applied problem. Simplified the algebraic expression. In the context of the applied problem, explain what your simplified algebraic expression represents.

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Answer from: bqg464

The algebraic equation represents the distance of the airplane with respect to the submarine is,

$\rm The \ difference \ between \ both \ elevation = x_a- x_s$

And the distance between the two elevations is 15,211 feet.

Given that,

An airplane flies at an altitude of 14,690 ft,

While a submarine is submerged at a depth of 521 feet below the surface of the ocean.

We have to determine,

What is the difference between these two elevations?

According to the question,

Let, x be the distance between a vehicle and sea level when the vehicle is above sea level, otherwise is below sea level.

The difference between an airplane $\rm x_a$ and $\rm x_s$ a submarine, measured in feet, is obtained by the following expression, that is:

$\rm The \ difference \ between \ both \ elevation = x_a- x_s$

Where $\rm x_a$ represents the distance of airplane with respect to sea levels.

And $\rm x_s$ represent the distance of the submarine with respect to sea levels.

Submerged at a depth of 521 feet below the surface of the ocean,

$\rm x_s = -521 \ feet$

Therefore,

The difference between an airplane $\rm x_a$ and $\rm x_s$ a submarine is,

$\rm The \ difference \ between \ both \ elevation = x_a- x_s\\\\ The \ difference \ between \ both \ elevation = 14,690-(-521)\\\\\rm The \ difference \ between \ both \ elevation = 15,211 \ feet$

Hence, The difference between these two elevations is 15,211 feet.

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Answer from: ellieflores8400

$d_{T} = d_{A}-d_{S}$ . The algebraic equation represents the distance of the airplane with respecto to the submarine. The distance between the two elevations is 15211 feet.

Step-by-step explanation:

Let be the distance between a vehicle and sea level, d 0 when vehicle is above sea level, otherwise is below sea level. The difference between airplane and submarine ( $d_{T}$ ), measured in feet, is obtained by the following expression, that is:

$d_{T} = d_{A}-d_{S}$

Where:

$d_{A}$ - Distance of airplane with respect to sea level, measured in meters.

$d_{S}$ - Distance of submarine with respect to sea level, measured in meters.

If we know that $d_{A} = 14690\,ft$ and $d_{S} = -521\,ft$ , then:

$d_{T} = 14690\,ft - (-521\,ft)$

$d_{T} = 15211\,ft.$

The algebraic equation represents the distance of the airplane with respecto to the submarine. The distance between the two elevations is 15211 feet.

Answer from: Quest

step-by-step explanation:

Answer from: Quest

jk it's 20

step-by-step explanation:

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