Find the derivative of the function. y = tan2(8θ)

16tan(8θ)sec²(8θ)

Step-by-step explanation:

Given the question :

Find the derivative of the function. y = tan2(8θ)

y = tan²(8θ)

USing chain rule :

dy/dx = (du/dx) × (dv/du) × (dy/dv)

Let u = 8θ ; du/dθ = 8

v = tan u ; dv/du = sec²u

y = v² ; dy/dv = 2v

Hence,

(dy/dθ) × dv/du × dy/dv

8 * sec²u * 2v

Where v = tan u ; u = 8θ

8 * sec²8θ * 2tan8θ

16tan(8θ)sec²(8θ)

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !