The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the and then a dilation by a scale factor of

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

1. 34

2. 268

3. x=14.4

step-by-step explanation:

greater than one

step-by-step explanation:

step-by-step explanation:

infinity is the answer