Find a formula for the general term an (not the partial sum) of each infinite series (with starting point of n = 1.)
4/12+1+1/22+1+4/32+1+1/42+1+

Answer and Explanation:

Solution: For the general term of each infinite series,

     n=1 and the series are:

4/12+1+1/22+1+4/32+1+1/42+1+……..

Let [4/12 +1] + [1/22 + 1] + [4/32+1] + [1/42+1] +………

Sum of infinite series= ∑n=1 [4/n+11 + 1/n] + [1/n+21 + 1/n] + [4/n+31 + 1/n] + [1/n+41 +1/n] +………..

For n=1.

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation