The equation of line lm is y = 5x + 4. write an equation of a line perpendicular to line lm in slope-intercept form that contains point (-3, 2).
select one:
a. y = -5x + 13
b. y= -1/5x + 7/5
c. y= 1/5x - 7/5
d. y= 5x-17

Y = 5x + 4...the slope here is 5...a perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So the slope we need is -1/5...see how I flipped the slope of 5, or 5/1, and changed the sign.

y = mx + b
slope(m) = -1/5
(-3,2)...x = -3 and y = 2
now we sub and solve for b, the y int
2 = -1/5(-3) + b
2 = 3/5 + b
2 - 3/5 = b
10/5 - 3/5 = b
7/5 = b
so ur perpendicular line is : y = -1/5x + 7/5

The slope of the line perpendicular to y = 5x + 4 is the negative reciprocal of the line specified. slope then is equal to -1/5. Subsituting to the point slope form equation, y - y1 = m(x-x1), y - 2 = -1/5 * (x + 3). y = -1/5 x -3/5 + 2 ; y = -1/5 x + 7/5 . Answer is B.