Which triangles are congruent? plz .

abc has vertices at a(12, 8), b(4, 8),and c(4, 14).

xyz has vertices at x(6, 6), y(4, 12),and z(10, 14).

mno has vertices at m(4, 16), n(4, 8),and o(-2, 8).

jkl has vertices at j(14, -2), k(12, 2),and l(20, 4).

Option C. is correct

Step-by-step explanation:

In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)

AB =

BC =

AC =

In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)

XY =

YZ =

XZ =

In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)

MN =

MO =

NO =

In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)

JK =

KL =

JL =

Now we compare the sides for the congruence

Since AB = MN = 8

BC = NO = 6

AC = OM = 10

So ΔABC ≅ Δ MNO

Option C. is correct

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺