the length of a rectangle is 3 inches more than it’s width. if the perimeter is 42 inches, find the dimensions of the rectangle

length = 12

width = 9

Step-by-step explanation:

We can use a system of linear equations to solve this problem. Lets make the variable L represent length and W represent width.

So we know that the length is 3 more than the width. An equation for this would be:

W = L - 3

We also know that the perimeter is 42 inches. The perimeter of a rectangle, using the variables L and W, is 2L + 2W, or 2(L + W). Using this, we can make the equation:

2(L + W) = 42

We can simplify the last equation by dividing both sides by 2:

L + W = 21

So now we have the two equations:

W = L - 3

L + W = 21

From here, there are multiple ways this question can be solved. I am going to use the substitution method here.

Knowing that W = L - 3, we can replace W in the second equation with L - 3.

L + L - 3 = 21

Add 3 to both sides.

2L = 24

Divide both sides by 2.

L = 12

Now we know that L = 12. Using this, we can replace L with 12 in the first equation to solve for W.

W = 12 - 3

W = 9

So:

L = length = 12

W = width = 9

I hope you find my answer helpful.

u bout ugly as   a mf

step-by-step explanation: lol

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it