At Al’s Athletic Club, the monthly membership fee for a student is \$25$25dollar sign, 25 and the monthly membership fee for an adult is \$40$40dollar sign, 40. If Al’s Athletic Club receives \$12{,}250$12,250dollar sign, 12, comma, 250 in membership fees for the month of January, which of the following represents the relationship between the number of student memberships, xxx, and the number of adult memberships, yyy, at Al’s Athletic Club for that month?

The equation represents the correct relationship.

Given, the no. of student memberships be represented by x and the number of adult memberships is represented by y.

The monthly membership fee for a student is $25.

The monthly membership fee for an adult is  $40.

Al’s Athletic Club receives money for the month of January is $12,500.

We have to make an equation to represent the situation that the club receives total money,

The required equation is,

.

Hence the equation represents the correct relationship.

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A. 25x + 40y = 12,250

Step-by-step explanation:

A. 25x+40y = 12,250

B. 40x+25y=12,250

C. x/25+y/40=12,250

D. x/40+y/25=12,250

Solution

Students membership fee = $25

Adult membership fee = $40

Total fees received by Al’s Athletic Club in the month of January = $12,250

The relationship between the number of student memberships x, and the number of adult memberships y, at Al’s Athletic Club for that month is

(Cost of students membership × number of students) + (Cost of adults membership × number of adults) = Total amount received by Al’s Athletic Club

(25 * x) + (40 * y) = 12,250

25x + 40y = 12,250

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40